When I run a go program from the shell, os.Args[0] is the program name. If
I invoke the same program using go's exec then os.Args[0] is not the
program name, rather its the first argument that I pass.
Here is a simple program to show this behavior, installed as gocmd in my
$GOPATH/bin
func main() {
fmt.Println(os.Args)
if os.Args[0] == "self" {
return
}
cmd := &exec.Cmd{
Path: <path to the program in $GOPATH/bin>,
Args: []string{"self", "selftest"},
Stdout: os.Stdout,
Stderr: os.Stderr,
}
if err := cmd.Run(); err != nil {
fmt.Println("Run failed..", err)
}
}
$ gocmd test1 test2
[gocmd test1 test2]
[self selftest]
$
Isn't the args[0] being the program name a behavior of exec call in Linux ?
What is the reason for this difference only for the binaries executed by
the exec package ?
thanks,
Santhosh.
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