How about a compromise with denser type info? (could consider an int8 as
well)
type infoType int
const (
firstType infoType = iota
secondType
...
)
type Info struct{
infoType
IData interface{}
}
On Wednesday, January 18, 2017 at 12:07:49 AM UTC-6, [email protected]
wrote:
>
> First thanks for you reply.
> Because in fact, I have about more than 10 different struct types (maybe
> more and more), your suggest is good, this is better
> type Info struct{
> typeStr string // store the type info to decode IData
> IData interface{}
> }
>
> But I don't like to send the typeInfo through rpc call（I'm using gob to do
> rpc call），maybe there's a better way to do it, just I haven't found it。
>
> 在 2017年1月18日星期三 UTC+8上午11:12:05，Felipe Spinolo写道：
>>
>> Why not just create a wrapper struct? Something like:
>>
>> type Mixed struct{
>> A *A
>> B *B
>> }
>>
>> And then just encode/decode that?
>>
>> On Tuesday, January 17, 2017 at 1:16:37 PM UTC-8, [email protected]
>> wrote:
>>>
>>> I got two struct types encoded into bytes by gob, I want to decode the
>>> bytes into a specific struct, is it possible without try all struct
>>> types(maybe 3 or more struct types)?
>>>
>>> I want to decode bytes without specify which elem in mixedBytes is
>>> struct A, and which is struct B.
>>> This is the playground url: https://play.golang.org/p/F0Wp5eWdGu
>>>
>>> Is is possible to implement it by a map or something like this?
>>>
>>> var typesMap = map[string]reflect.Value{
>>> "A": reflect.ValueOf(A{}),
>>> "B": reflect.ValueOf(B{}),
>>> }
>>>
>>>
>>>
>>>
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