If you had this
type I interface { ... }
type T struct {
sync.Mutex
}
var t T
var i I = t
This is a mistake because a *copy* of the contents of t is assigned to i.
Every assignment in Go is a copy, there are no exceptions.
To solve this assignment the *address* of t to I.
var i I = &t
Or more suscinctly
var i I = &T{ .... }
--
You received this message because you are subscribed to the Google Groups
"golang-nuts" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/d/optout.
