On Sun, Feb 2, 2014 at 8:59 AM, Martin Erik Werner
<[email protected]> wrote:
> + /* check if work tree is already the prefix */
> + if (strncmp(path, work_tree, wtlen) == 0) {
> + if (path[wtlen] == '/')
> + memmove(path, path + wtlen + 1, len - wtlen);
> + else
> + /* work tree is the root, or the whole path */
> + memmove(path, path + wtlen, len - wtlen + 1);
> + return 0;
> + }
No the 4th time is not the charm yet :) if path is "/abc/defghi" and
work_tree is "/abc/def" you don't want to return "ghi" as the prefix
here.
> + path0 = path;
> + path += offset_1st_component(path);
> +
> + /* check each level */
> + while (*path != '\0') {
> + path++;
To me it looks like we could write
for (; *path; path++) {
or even
for (path += offset_1st_component(path); *path; path++) {
but it's personal taste..
> + if (*path == '/') {
> + *path = '\0';
> + if (strcmp(real_path(path0), work_tree) == 0) {
> + memmove(path0, path + 1, len - (path -
> path0));
> + return 0;
> + }
> + *path = '/';
> + }
> + }
> +
> + /* check whole path */
> + if (strcmp(real_path(path0), work_tree) == 0) {
> + *path0 = '\0';
> + return 0;
> + }
I think this is already handled by the "check if work tree is already
the prefix" block.
> +
> + return -1;
> +}
> +
> +/*
> * Normalize "path", prepending the "prefix" for relative paths. If
> * remaining_prefix is not NULL, return the actual prefix still
> * remains in the path. For example, prefix = sub1/sub2/ and path is
> --
> 1.8.5.2
>
--
Duy
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