Ilya Leoshkevich via Gcc <gcc@gcc.gnu.org> writes: > On Wed, 2020-09-09 at 16:09 -0500, Segher Boessenkool wrote: >> Hi Ilya, >> >> On Wed, Sep 09, 2020 at 11:50:56AM +0200, Ilya Leoshkevich via Gcc >> wrote: >> > I have a vector pseudo containing a single 128-bit value (V1TFmode) >> > and >> > I need to access its last 64 bits (DFmode). Which of the two >> > options >> > is better? >> > >> > (subreg:DF (reg:V1TF) 8) >> > >> > or >> > >> > (vec_select:DF (subreg:V2DF (reg:V1TF) 0) (parallel [(const_int >> > 1)])) >> > >> > If I use the first one, I run into a problem with set_noop_p (): it >> > thinks that >> > >> > (set (subreg:DF (reg:TF %f0) 8) (subreg:DF (reg:V1TF %f0) 8)) >> > >> > is a no-op, because it doesn't check the mode after stripping the >> > subreg: >> > >> > https://gcc.gnu.org/git/?p=gcc.git;a=blob;f=gcc/rtlanal.c;h=5ae38b79#l1616 >> > >> > However this is not correct, because SET_DEST is the second >> > register in >> > a register pair, and SET_SRC is half of a vector register that >> > overlaps >> > the first register in the corresponding pair. So it looks as if >> > mode >> > needs to be considered there. >> >> Yes. >> >> > This helps: >> > >> > --- a/gcc/rtlanal.c >> > +++ b/gcc/rtlanal.c >> > @@ -1619,6 +1619,8 @@ set_noop_p (const_rtx set) >> > return 0; >> > src = SUBREG_REG (src); >> > dst = SUBREG_REG (dst); >> > + if (GET_MODE (src) != GET_MODE (dst)) >> > + return 0; >> > } >> > >> > but I'm not sure whether I'm not missing something about subreg >> > semantics in the first place. >> >> You probably should just see if both modes are the same number of >> hard >> registers? HARD_REGNO_NREGS. > > I've refined my patch as follows: > > --- a/gcc/rtlanal.c > +++ b/gcc/rtlanal.c > @@ -1619,6 +1619,11 @@ set_noop_p (const_rtx set) > return 0; > src = SUBREG_REG (src); > dst = SUBREG_REG (dst); > + if (REG_P (src) && HARD_REGISTER_P (src) && REG_P (dst) > + && HARD_REGISTER_P (dst) > + && hard_regno_nregs (REGNO (src), GET_MODE (src)) > + != hard_regno_nregs (REGNO (dst), GET_MODE (dst))) > + return 0; > }
I think checking the mode would be safer. Having the same number of registers doesn't mean that the bits are distributed across the registers in the same way. Out of interest, why can't the subregs in the example above get folded down to hard registers? Thanks, Richard
