[EMAIL PROTECTED] wrote:
>
> #include <stdio.h>
> #include <math.h>
>
> int main()
> {
> printf("\n %1.55f \n", sqrt(3.9999999999999999));
> return 0;
> }
>
> Result: 2
>
> Why does this return 2 ??If you meant to use long double, you should have so specified. Decimal digits beyond 17 aren't significant in conversion to IEEE 64-bit double. Some of the properties of the floating point data types are shown in <float.h>. Just as a matter of curiosity, how did you get this message marked as spam?
