Quoting Tom Tromey <[EMAIL PROTECTED]>:
"Antoine" == Antoine Eiche <[EMAIL PROTECTED]> writes:
Without more information I don't know how to answer your question.
But I do have a question for you...
Antoine> I must calculate the address of an element's array.
Antoine> If the size of an element is one integer it's good.
Antoine> I do like that:
Antoine> new_rhs=fold_build2(PLUS_EXPR,TREE_TYPE(TREE_OPERAND(rhs,1)),
Antoine> build1(ADDR_EXPR, build_pointer_type
(TREE_TYPE
Antoine> (array)),array),
Antoine> index);
Why not use ARRAY_REF here? Then you don't have to worry about the
size of an element of the array.
Tom
I tested whit ARRAY_REF but I did not succeed to build the address
(error when I test my pass).
Then, I try to calculate the address whit the index and the size of an
element.
I specify that I just have the problem whit a static array.
This code is the code which is in the source file of a test program:
int main()
{
int a[10];
int i;
for(i=0;i<10;i++){
a[i]=1;
}
}
I have succeed to transform the code like that:
int main(){
int a[10];
int i;
for(i=0;i<10;i++){
foo(a + i);
a[i]=1;
}
}
But I want to transform like that:
int main(){
int a[10];
int i;
for(i=0;i<10;i++){
foo(a + i * sizeof(*a));
a[i]=1;
}
}
I specify that I have not succeed to transform like that!:
int main(){
int a[10];
int i;
for(i=0;i<10;i++){
foo(& a[i]);
a[i]=1;
}
}
Why can I not do "foo(a + i * x)" then I can do "foo(i * x)" ou "foo(a
+ i)" ?*
How can I do that ?
Thanks in advance.
