In gcc the file emutls.c assumes that a long has sizeof void * in function emutls_destroy.
Regards, i.A. Kai Tietz ---------------------------------------- Kai Tietz - Software engineering OneVision Software Entwicklungs GmbH & Co KG Dr.-Leo-Ritter-Str. 9, 93049 Regensburg, Germany Phone: +49-941-78004-0 FAX: +49-941-78004-489 WWW: http://www.OneVision.com Ian Lance Taylor <[EMAIL PROTECTED]> 08.03.2007 18:02 To Kai Tietz <[EMAIL PROTECTED]> cc gcc@gcc.gnu.org Subject Re: What does coding-style tells about integer types for pointers ? Kai Tietz <[EMAIL PROTECTED]> writes: > while porting gcc to the new target x86_64-pc-mingw32 I noticed, that on > many places the long type is wrongly used as equivalent for pointers. This > leads for this MS compatible target to some problems, because the long is > just 4 bytes long and the pointer 8 bytes. I found this problems until now > in libc++, libiberty. There are ISO types defined for this case, as > intptr_t and uintptr_t. Is there something defined in the coding style ? Code in gcc which assumes that sizeof (long) == sizeof (void *) is broken. Tell us where that code is, and we will try to fix it. Ian
