"Hongbo Li" <[EMAIL PROTECTED]> writes:
This question would be more appropriate for the gcc-help mailing list
rather than the gcc mailing list.
> I currently hit an issue that I would like to use a function
> statically linked to a shared library but my program use the same
> function from another shared library. Here is what I do:
>
> 1. I have toto.cxx that has one function called: toto() {cout <<
> "static toto" << endl;}
> 2. I create an archive say toto.a has the toto.o
> 3. I have toto1.cxx that has one functin called toto() {cout
> cout <<"shared toto"<<endl;}
> 4. I create a shared libtoto1.so
> 5. I have use_toto.cxx that has one function called use_toto() {
> toto();}:
> 6. I create a shared libuse_toto.so that statically link to
> toto.a
> 7. My main program test.cxx calling use_toto()
>
> I would like to always see the output of "static toto" but the
> output depends on the order of linking toto1.so and use_toto.so
>
> I will see "static toto" when I do this
> g++ -o test -L./ -luse_toto -ltoto1.so ./test.o
>
> But I see "shared toto" if I change the order:
> g++ -o test -L./ -ltoto1.so -luse_toto ./test.o
>
>
> My question: do we have any way during the compilation/link to
> control the program so that toto() in toto.cxx is always used? Since I
> may not have way to control how to build the main program, is there a
> way to build libuse_toto.so so that toto() in toto.cxx is always used?
As you have discovered, the order on the link line determines when
symbols will be used.
You can force a few other possibilities by using a linker version
script or by setting the visibility attributes. See the linker manual
for version scripts and the gcc manual for attributes.
Ian
