On Mon, Dec 05, 2005 at 03:27:56PM +0100, [EMAIL PROTECTED] wrote: > Shouldn't the compiler behave in the following way, concerning the signedness > of pointer arguments? > > void f (long *l, signed long *sl, unsigned long *ul);
"long" and "signed long" are the same type. You are confused about how C and C++ are defined. Same with "int" and "signed int". Only for "char" are things different; it is implementation-defined (can differ from platform to platform) whether "char" is signed or not.
