On Sat, 14 Jun 2025 at 13:32, саша савельев wrote:
>
>
> To whom it may concern
>
> Why we can’t use <const char*> in this context?
>
> #include < iostream >
> template < auto N >
> void f () {
> std::cout << N << std::endl ;
> }
> int main () {
> f < 1 >();
> f < '!' >();
> f < "!!" >(); // error
> return 0 ;
> }
Hello, this is a general C++ question, so is off topic on this mailing
list which is for discussing the development of GCC. Somewhere like
stackoverflow.com would be more appropriate for learning how C++
works.
The reason you can't do this is because the C++ standard says you can't:
https://wg21.link/temp.arg.nontype#6
I think the reason is that the address of a string literal is not
portable, even between different source files:
https://wg21.link/lex.string#note-4
It's unspecified whether calling f<"!!">() in two different places
would even be the same specialization of the template, or a different
specialization each time. To avoid surprises and non-portable
behaviour, you're just not allowed to do that.
>
>
> Alexander and his classmates
