On Mon, Jul 11, 2005 at 08:07:20PM +0200, Sylvester Diehl wrote: > why doesn't gcc (-Wall -Wuninitalized -O) detect > an uninialized variable passed by reference > decleared as <type> const *<name> ?
There are no uninitialized variables in your program. For the kind of access checking you seem to be asking for, you'll need something like valgrind or mudflap. > int foo(int const *p) > { > static int sum = 0; > > sum += *p; > return sum; > } it happens that the memory that p points to is unitialized, but that is not what -Wuninitialized does. Similarly, in > int main(int argc, char **argv) > { > int k; > > return printf("%d\n", foo(&k)); > } there are no uninitialized variables, as the address of k is perfectly well defined. > p.s. i know i could pass the variable by value > to get a warning of an uninitalized variable. Yes, because then there will *be* an unitialized variable.