| signed types are undefined on overflow. [5/5] and [3.9.1/2,3] > But a compiler could define them to be modulo -- that is the whole > point. The paragraph does not say they don't "modulo".
True, but you are going to have to deal with the run-time version of
(int)0x80000000 / -1
which is unpleasant in the sense that Intel processors will trap and not
do anything modulo-like.
Morten
