> int bar [ 4 * 256 ] = { 0,1,2, ... };
>
> I did not changed nor any compiler option, neither any
> declaration. I still cannot see the difference in between those
> two, since the declaration is exactly the same. The only difference
> being a default initialization.
There is a more subtle diffrence at work here. According to ANSI:
``An external declaration for an object is a definition if it has an
initalizer.
*An external object declaration that does not have an initalizer, and does not
contain the extern specifier, is a tentaive definition.* If a definition for
an
object appears in a translation unit, all its tentative definitions become a
single definition with initalizer 0.''
The highlighted sentence is very subtle, but it is the entire diffrence between
an executables `text' and `bss' sections. In Darwin, ``tentative definition''
is called ``common symbol''. _When you add the initalizer, you make the
definition non-tentative_. Got it? (If not, you should reread this paragraph.)
The moral of the story is, be sure to always read the fine print.
(Translation:
keep track of subtleties when doing work.)
Samuel Lauber
--
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