Re: How to get MIN_EXPR without using deprecated min operator

[chris jefferson]

Michael Cieslinski wrote:
Consider the following short program:
   #include <algorithm>
   
   void Tst1(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
   {
       for (int x=0; x<Len; x++)
           MinP[x] = SrcP[x] <? MinP[x];
   }
   
   void Tst2(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
   {
       for (int x=0; x<Len; x++)
           MinP[x] = std::min(SrcP[x], MinP[x]);
   }

If I compile it with
   gcc41 -O2 -ftree-vectorize -ftree-vectorizer-verbose=5
function Tst1 gets vectorized but Tst2 not.
The reason for this is <? results in a MIN_EXPR while std::min generates a
conditional code.
My question is, how can I get a MIN_EXPR without using the deprecated min <?
operator?
 

Out of interest, do you get vectorisation from:
MinP[x] = (SrcP[x]<MinP[x]) ? SrcP[x] : MinP[x];
Chris