On 2005-04-27 15:44:15 +0100, Dave Korn wrote:
> ----Original Message----
> >From: Vincent Lefevre
> >Sent: 27 April 2005 14:59
>
> > On 2005-04-27 15:30:39 +0200, Gabriel Dos Reis wrote:
> >> Vincent Lefevre <[EMAIL PROTECTED]> writes:
> >>
> >> [...]
> >>
> >>>> > But if they are never modified, they evaluate to constants, right?
> >>>> > > The fact that they are not considered as constant expressions,
> >>>> > is it due to the fact that the environment is allowed to modify >
> >>>> them?
> >>>>
> >>>> It's due to what the C standard says. A const variable in C isn't a
> >>>> constant, it's just a read-only variable.
> >>>
> >>> 1+1 isn't a constant either
> >>
> >> It is an integer constant expression, and its evaluation yields a
> >> constant (see 6.6). Can you explain why you believe that is false?
> >
> > I never said that it was false.
>
> Yes you did. You _implied_ it.
No.
> You said "1+1 isn't a constant either".
Yes. FYI, here are the constants:
6.4.4 Constants
Syntax
[#1]
constant:
integer-constant
floating-constant
enumeration-constant
character-constant
I cannot see any form for 1+1 here.
> Gabriel said that it is a constant, and explained precisely why it
> is a constant.
Gabriel said that it evaluates to a constant. And I don't disagree
with him here.
--
Vincent Lefèvre <[EMAIL PROTECTED]> - Web: <http://www.vinc17.org/>
100% accessible validated (X)HTML - Blog: <http://www.vinc17.org/blog/>
Work: CR INRIA - computer arithmetic / SPACES project at LORIA
