#define optimize 0
"optimize" is a variable and "int 0" won't parse, so that won't come close.
I didn't see a patch there that I said was complete and survived a bootstrap. It was a sketch of an idea.
What did you really mean?
Just what I said.
int optimize = 0
trivially becomes:
#ifndef optimize int optimize = 0; #endif
I didn't try and go out of my way to be obtuse.
Turning off optimization is not going to get you the smallest code size
We was talking about the size of the compiler binary, not of generated code. He can evaluate if non-optimal code is permissible in his case, certainly he left out so many details as to not allow me to guess.
since many optimizations reduce it
? I didn't say that he had to bootstap the compiler, in fact, obviously, one would want to avoid that, in fact, I did mean it to be implicit in what I said, as otherwise:
if (optimize)
foo();would not optimize away to make small code.
...the option intended to produce smallest code is -Os.
Agreed.
