On Tue, Nov 18, 2014 at 11:19 AM, Paolo Carlini
<paolo.carl...@oracle.com> wrote:
> Jonathan lately is following your work much better than me, but naively
> seems weird that _M_begin is non-const and _M_end is const, a different type
> anyway.
Hmm. The current regex_search algorithm is implemented as try match
starting from _M_begin; if it doesn't match, start over from
_M_begin+1, ...
As we can tell, _M_begin is never changed, and it's const.
The problem is when the executer reaches the accept state (which
indicates a match) we use _M_current == _M_begin to verify if it's an
empty match. It is possible that, when we are not in the first
iteration, say, in the second iteration actually, _M_current is
initialized with _M_begin+1. It turns out even _M_current has never
been increased (no chars are eaten, aka empty match), _M_current !=
_M_begin is still true.
This fix is making each regex_search iteration more thorough, with
increased _M_begin, as if it's a new regex _M_search_from_first.
I've carefully (admittedly, after sending this patch) inspect
everywhere when _M_begin is used. It turns out _M_begin is under
well-defined (the initial position of _M_current when current
iteration starts) invariants (see _Executor<>::_M_at_begin), indicated
by the use of regex_constants::match_prev_avail. This flag actually
implies that __begin iterator passed into regex_search is not always
"the physical boundary" who matches "^". Boost (and we) conforms this
behavior:
std::regex_search("asdf", std::regex("^asdf"),
std::regex_constants::match_prev_avail)
returns false.
It's more elegant to move _Executor::_M_search out of its class and
make _M_begin still const, but _Executor costs too much to initialize.
--
Regards,
Tim Shen
