On Mon, Nov 25, 2013 at 10:26 AM, Diego Novillo <dnovi...@google.com> wrote: > On Mon, Nov 25, 2013 at 1:22 PM, Xinliang David Li <davi...@google.com> wrote: >> In this case the backedge will be a critical edge, which will be split by >> GCC. > > Right. So, if I split it, I will reach essentially the same > conclusion, I think. The new block will get the original block's > weight, which (in turn) will translate into the (now only outgoing) > edge.
Why do you want to set the back edge count as the BB count? I think the right formula is: count(back_edge) = count(BB) - count(entry_edge), in which entry_edge is the edge that enters the loop. Dehao > > > Diego.
