Re: [C++] Handle ?: for vectors

[Jason Merrill]

On 10/19/2012 04:40 PM, Marc Glisse wrote:
So between the following:
a) x?y:z means (x<0)?y:z
b) x?y:z means (x!=0)?y:z
c) x?y:z is rejected, only things like (x==t)?y:z are accepted
d) other
is the choice still b) ? That's an easy one, only 2 characters to change
in the patch (assuming the rest is correct) :-)

That would be my inclination, but I'm not a vector programming expert, 
so I guess let's go with the OpenCL semantics.

Jason