On 10/27/2016 05:57 PM, Bernd Edlinger wrote:
In the function below we have if ((UWtype)u == u)
that actually ensures hi != 0.

Ah, right. So maybe we ought to just add the same case here as well?

  if ((UWtype)u == u)
    return (FSTYPE)(UWtype)u;

That would also make the comment less misleading. The condition should ensure that u is positive and representable in UWtype, so this should be correct, right?


Bernd

Reply via email to