------- Additional Comments From manus at eiffel dot com 2004-11-09 23:32
-------
This is not undefined, I know which feature I'm calling. It is `f'. Moreover I
provide the right function cast which matches how `f' is actually declared.
What strikes me the most is that you reject:
((void (*) (char)) f)(a);
but allow:
void * fnptr = f;
((void (*) (char)) fnptr)(a);
This is rather surprising.
Regards,
Manu
--
What |Removed |Added
----------------------------------------------------------------------------
Status|RESOLVED |UNCONFIRMED
Resolution|INVALID |
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=18411
