------- Additional Comments From schlie at comcast dot net 2004-10-20 21:46 -------
Subject: Re: usual arithmetic conversion not applying
correctly
Andrew,
And if it's already declared as, or cast to signed char's in the code?
unsigned char x, y ;
(signed char)x = (signed char)x / (signed char)y ;
-or- (should yield identical code, and require no promotions or conversions)
signed char x, y ;
x = x / y ; the only arguable possible type conversion that may be required
; would be to convert the result of (x / y) which may have been
; implemented by the target machine as having a wider result, but
; not required if it's destination storage does not require it.
(there's no reason to ever muck with specified object types unless it's
value needs to converted as required for assignment, or the specified
semantics of an operation; but even then, the type of the object doesn't
change, although the its value's representation may if required.)
-paul-
> From: pinskia at gcc dot gnu dot org <[EMAIL PROTECTED]>
> Reply-To: <[EMAIL PROTECTED]>
> Date: 20 Oct 2004 19:54:55 -0000
> To: <[EMAIL PROTECTED]>
> Subject: [Bug c/18065] usual arithmetic conversion not applying correctly
>
>
> ------- Additional Comments From pinskia at gcc dot gnu dot org 2004-10-20
> 19:54 -------
> When I am talking about promoting means that we add casts. aka sc%sc gets
> changed to (signed char)
> (((int)sc)%((int)sc)).
>
> --
>
>
> http://gcc.gnu.org/bugzilla/show_bug.cgi?id=18065
>
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--
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=18065
