https://gcc.gnu.org/bugzilla/show_bug.cgi?id=117817
Bug ID: 117817
Summary: Compile error when taking address of temporary array
in sizeof operator
Product: gcc
Version: 13.3.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: odion at efficios dot com
Target Milestone: ---
The following program compiles fine with all versions of GCC except for version
13.
a-bug.ii:
# 0 "bug.cpp"
# 0 "<built-in>"
# 0 "<command-line>"
# 1 "/usr/include/stdc-predef.h" 1 3
# 0 "<command-line>" 2
# 1 "bug.cpp"
constexpr int c = 1;
struct e {
int *b;
};
struct {
long d;
} a{sizeof e{(int[]){c}}};
int main() {}
error:
bug.cpp:7:21: error: taking address of temporary array
7 | } a{sizeof e{(int[]){c}}};
|
command:
g++ a-bug.ii
Toolchain:
Target: x86_64-unknown-linux-gnu
Configured with:
Thread model: posix
Supported LTO compression algorithms: zlib
gcc version 13.3.0 (GCC)
System:
Guix System
--
What I find weird is that an error is reported for taking the address of a
temporary array in a sizeof() operator.
What is even weirder is that if you change the expression `constexpr int c =
1;'
to `#define c 1', then there is no error. However, changing it to `enum { c
};'
does trigger the same error.
