https://gcc.gnu.org/bugzilla/show_bug.cgi?id=116852
Bug ID: 116852
Summary: -fvisibility-inlines-hidden does not hide template
functions without 'inline'
Product: gcc
Version: 14.1.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: [email protected]
Target Milestone: ---
# Consider this code:
cat > t.cc <<EOF
template<class T> void templateFunc() { }
template<class T> inline void templateFuncInline() { }
struct Bar
{
void memberFunc() {}
inline void memberFuncInline() {}
template<class T> void templateMemberFunc() {}
template<class T> inline void templateMemberFuncInline() {}
};
void func()
{
templateFunc<int>();
templateFuncInline<int>();
Bar b;
b.memberFunc();
b.memberFuncInline();
b.templateMemberFunc<int>();
b.templateMemberFuncInline<int>();
}
EOF
# Compiled with
g++ t.cc -o t.so -shared -fvisibility-inlines-hidden
# Symbols
readelf --dyn-syms -W t.so
##########################
Outputs a weak default visible symbol for templateFunc
> 5: 0000000000001165 7 FUNC WEAK DEFAULT 12
> _Z12templateFuncIiEvv
but all the other functions will not be default visible.
Aren't functions templates implicitly declared inline in C++, like inline
defined member functions?
Shouldn't the instantiations then also be hidden? A lot of our dynamic symbols
are such functions.
Adding inline everywhere will fix the issue for us, but this also effects
thrid-party code.
Is there another way to treat templateFunc as inline in the sense of
-fvisibility-inlines-hidden?
