https://gcc.gnu.org/bugzilla/show_bug.cgi?id=111466
Bug ID: 111466
Summary: RISC-V: redundant sign extensions despite ABI
guarantees
Product: gcc
Version: 13.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: target
Assignee: vineetg at gcc dot gnu.org
Reporter: vineetg at gcc dot gnu.org
CC: aagarwa at gcc dot gnu.org, jeffreyalaw at gmail dot com,
jivanhakobyan9 at gmail dot com, kito at gcc dot gnu.org,
palmer at gcc dot gnu.org
Target Milestone: ---
Consider the test below:
int foo(int unused, int n, unsigned y, unsigned delta){
int s = 0;
unsigned int x = 0; // if int, sext elided
for (;x<n;x +=delta)
s += x+y;
return s;
}
-O2 -march=rv64gc_zba_zbb_zbs
foo2:
sext.w a6,a1 # 1
beq a1,zero,.L4
li a5,0
li a0,0
.L3:
addw a4,a2,a5
addw a5,a3,a5
addw a0,a4,a0
bltu a5,a6,.L3
ret
.L4:
li a0,0
ret
I believe the SEXT.W is not semantically needed as a1 is supposed to be sign
extended already at call site as per psABI [1]. I quote
"When passed in registers or on the stack, integer scalars narrower than
XLEN bits are widened according to the sign of their type up to 32 bits, then
sign-extended to XLEN bits"
However currently RISC-V backend thinks otherwise: changing @x to int, causes
the the sign extend to go away. I think both the cases should behave the same
(and not generate SEXT.w) given the ABI clause above. Note that this manifests
in initial RTL expand itself generating/or-not-generating the sign_extend so if
it is unnecessary we can avoid late fixups in REE.
Andrew Waterman confirmed that the ABI guarantees this and that the SEXT.W is
redundant [1]
[1] https://gcc.gnu.org/pipermail/gcc-patches/2023-September/630811.html