https://gcc.gnu.org/bugzilla/show_bug.cgi?id=110437
Bug ID: 110437 Summary: SIGILL when return missing in a C++ function with a condition Product: gcc Version: 13.1.1 Status: UNCONFIRMED Severity: normal Priority: P3 Component: c++ Assignee: unassigned at gcc dot gnu.org Reporter: jan.zizka at nokia dot com Target Milestone: --- Created attachment 55404 --> https://gcc.gnu.org/bugzilla/attachment.cgi?id=55404&action=edit Reproducer fails with g++ With gcc 13 following code triggers SIGILL: #include<iostream> int func1() { int value = 1; if (value == 1) { std::cout << "ONE" << std::endl; } else { std::cout << "ZERO" << std::endl; } } int main() { func1(); } To reproduce: g++ -o reproduce reproduce.cpp ./reproduce Resulting with: ONE [1] 19714 illegal hardware instruction (core dumped) ./reproduce Warning is generated by compiler: reproduce.cpp: In function ‘int func1()’: reproduce.cpp:10:1: warning: no return statement in function returning non-void [-Wreturn-type] 10 | } | ^ With similar C code the SIGILL is not triggered: #include<stdio.h> int func1() { int value = 1; if (value == 1) { printf("ONE\n"); } else { printf("ZERO\n"); } } int main() { func1(); } Warning is still generated with -Wall. Is there some reason this behaves differently in C and C++? And shouldn't rather compiler throw error instead of warning if this will crash in runtime? We have caught this on some very old legacy code which just had missing return statement and with upgrade to gcc 13.1.1 we have started to see SIGILL in runtime. Based on disassembled code the compiler emits ud2 instruction triggering SIGILL. With gcc 12.2 at least the same code doesn't trigger SIGILL. I didn't check the disassembly. I have run this on Fedora 38 and I didn't try to bisect which exact commit triggers this. If it would be useful I can run bisect.