https://gcc.gnu.org/bugzilla/show_bug.cgi?id=109500
--- Comment #4 from anlauf at gcc dot gnu.org --- I think one cannot achieve what the OP wants by using allocable function results. One should use a subroutine instead. Compiling the code with the NAG compiler gives: NAG Fortran Compiler Release 7.1(Hanzomon) Build 7101 Warning: pr109500.f90, line 7: Allocatable function F has not been allocated or assigned a value Error: pr109500.f90, line 2: Expected an ALLOCATABLE variable for argument P (no. 1) of IS_ALLOCATED [NAG Fortran Compiler error termination, 1 error, 1 warning] Not perfect, but what you are seeing is an attempt by the compiler to do argument association when you invoke function is_allocated. Now look at the following variants in the main: 1) print *, allocated(f()) You'll get: 2 | print *, allocated(f()) | 1 Error: 'array' argument of 'allocated' intrinsic at (1) must be a variable This is what the standard says. 2) integer, allocatable :: p p = f() print *, allocated(p) This compiles, but you get a runtime error (SIGSEGV) with gfortran and ifort. Why? The assignment p=f() is invalid for unallocated r.h.s., and you are hitting this. The running program will never reach the allocated(p). I don't see a legal way to use an allocatable function without allocating the result. So you should use a subroutine and allocate a result variable. The only potential issue I see here with gfortran is that there is no working runtime diagnostics for the non-allocated r.h.s. above. But there is none for current ifort/ifx either. If the reporter agrees, we should close this PR as invalid.