https://gcc.gnu.org/bugzilla/show_bug.cgi?id=105473
--- Comment #19 from harper at msor dot vuw.ac.nz ---
Thank you. To make the outputs from my test program testdecimal.f90 easier
to compare when using different compilers, and to clarify where a reading
error happened, I have revised the program to make its results clearer.
Below is the new version of the program. I see no point in sending its
output with my gfortran, which does not have Jerry's latest corrections,
but I do provide its output with ifort, which it is not your job to debug!
john@johns-laptop:~/Jfh$ cat testdecimal.f90
! Test list-directed reading with decimal='point' and 'comma' by
! printing one line for each of 32 cases, reading input(1:16) with each
! of 'point' or 'comma', using s(ios) to give ERR, OK or end according
! to the iostat=ios value from reading. Before reading, x=[666,999].
implicit none
real x(2)
integer ios,i,j
character(*),parameter:: punc=",; .",fmt='(1X,A,I2,1X,5A,2F7.1,1X,A)'
integer,parameter:: lpunc =len(punc)
character:: dec(2)*5=['point','comma'], input(lpunc**2)*4 = &
[(("2"//punc(i:i)//"5"//punc(j:j),i=1,lpunc),j=1,lpunc)]
do i = 1,size(input)
do j = 1,2
x = [666, 999]
read(input(i),*,decimal=dec(j),iostat=ios) x
print fmt,'i=',i,' input="',input(i),'" with ',dec(j),&
' x =',x,s(ios)
end do
end do
contains
character(3) function s(ios) ! ERR, OK ,end if ios>0, ==0, <0
integer,intent(in):: ios
s = merge('ERR',merge(' OK','end',ios==0),ios>0)
end function s
end program
john@johns-laptop:~/Jfh$ ifort testdecimal.f90; ./a.out
Compiling "ifort testdecimal.f90"
i= 1 input="2,5," with point x = 2.0 5.0 OK
i= 1 input="2,5," with comma x = 666.0 999.0 ERR
i= 2 input="2;5," with point x = 666.0 999.0 ERR
i= 2 input="2;5," with comma x = 2.0 5.0 OK
i= 3 input="2 5," with point x = 2.0 5.0 OK
i= 3 input="2 5," with comma x = 2.0 5.0 OK
i= 4 input="2.5," with point x = 2.5 999.0 end
i= 4 input="2.5," with comma x = 666.0 999.0 ERR
i= 5 input="2,5;" with point x = 2.0 999.0 ERR
i= 5 input="2,5;" with comma x = 2.5 999.0 end
i= 6 input="2;5;" with point x = 666.0 999.0 ERR
i= 6 input="2;5;" with comma x = 2.0 5.0 OK
i= 7 input="2 5;" with point x = 2.0 999.0 ERR
i= 7 input="2 5;" with comma x = 2.0 5.0 OK
i= 8 input="2.5;" with point x = 666.0 999.0 ERR
i= 8 input="2.5;" with comma x = 666.0 999.0 ERR
i= 9 input="2,5 " with point x = 2.0 5.0 OK
i= 9 input="2,5 " with comma x = 2.5 999.0 end
i=10 input="2;5 " with point x = 666.0 999.0 ERR
i=10 input="2;5 " with comma x = 2.0 5.0 OK
i=11 input="2 5 " with point x = 2.0 5.0 OK
i=11 input="2 5 " with comma x = 2.0 5.0 OK
i=12 input="2.5 " with point x = 2.5 999.0 end
i=12 input="2.5 " with comma x = 666.0 999.0 ERR
i=13 input="2,5." with point x = 2.0 5.0 OK
i=13 input="2,5." with comma x = 666.0 999.0 ERR
i=14 input="2;5." with point x = 666.0 999.0 ERR
i=14 input="2;5." with comma x = 2.0 999.0 ERR
i=15 input="2 5." with point x = 2.0 5.0 OK
i=15 input="2 5." with comma x = 2.0 999.0 ERR
i=16 input="2.5." with point x = 666.0 999.0 ERR
i=16 input="2.5." with comma x = 666.0 999.0 ERR
john@johns-laptop:~/Jfh$
On Wed, 18 May 2022, jvdelisle at gcc dot gnu.org wrote:
> Date: Wed, 18 May 2022 02:52:26 +0000
> From: jvdelisle at gcc dot gnu.org <[email protected]>
> To: John Harper <[email protected]>
> Subject: [Bug fortran/105473] semicolon allowed when list-directed read
> integer with decimal='point'
> Resent-Date: Wed, 18 May 2022 14:52:38 +1200 (NZST)
> Resent-From: <[email protected]>
>
> https://gcc.gnu.org/bugzilla/show_bug.cgi?id=105473
>
> --- Comment #18 from Jerry DeLisle <jvdelisle at gcc dot gnu.org> ---
> (In reply to harper from comment #17)
>> On comparing that with ifort's result I think that the only remaining bug
>> is that if decimal='comma' then '.' is neither a decimal symbol nor a
>> separator (see f2018 13.6).
>
> Making this easier for others to see.
>
> With gfortran I see with the 8th sub-case:
>
> i= 8 input(i) = "2.5;"
> with decimal=point x(:) =2.5 666.0 ios=5010
> with decimal=comma x(:) =2.5 666.0 ios=-1
>
> i= 12 input(i) = "2.5 "
> with decimal=point x(:) =2.5 666.0 ios=-1
> with decimal=comma x(:) =2.5 666.0 ios=-1
>
> In these cases the decimal=comma should have never seen 2.5
>
> With ifort:
>
> i= 8 input(i) = "2.5;"
> with decimal=point x(:) = 2.50000000 5.00000000 ios= 5010
> with decimal=comma x(:) = 2.50000000 666.000000 ios= -1
>
> I don't think ifort has the decimal=point part right, as if it backed up and
> read the digit 5 a second time.
>
> Regardless, getting closer here. I will work on the gfortran comma issue.
>
> --
> You are receiving this mail because:
> You reported the bug.
>
-- John Harper, School of Mathematics and Statistics
Victoria Univ. of Wellington, PO Box 600, Wellington 6140, New Zealand.
e-mail [email protected] phone +64(0) 4 463 5276
