https://gcc.gnu.org/bugzilla/show_bug.cgi?id=103721
Andrew Pinski <pinskia at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Last reconfirmed| |2021-12-14
Status|UNCONFIRMED |NEW
Ever confirmed|0 |1
--- Comment #1 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
Confirmed.
Here is one which does not use pointers and inlining does not matter:
int ipos = 0;
int f (int world)
{
int searchVolume = world;
int currentVolume = 0;
while (currentVolume != searchVolume && searchVolume) {
currentVolume = searchVolume;
if (ipos != 0)
searchVolume = 0;
else
searchVolume = 1;
}
return (currentVolume);
}
int main()
{
const int i = f (1111);
__builtin_printf ("%d\n", (int)(i));
if (i != 1)
__builtin_abort ();
return 0;
}