https://gcc.gnu.org/bugzilla/show_bug.cgi?id=39843
Andrew Pinski <pinskia at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Last reconfirmed| |2021-08-05
Ever confirmed|0 |1
Status|UNCONFIRMED |NEW
--- Comment #3 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
Confirmed.
C front-end:
/* Adjust the type if a bit-field is being declared,
-funsigned-bitfields applied and the type is not explicitly
"signed". */
if (bitfield && !flag_signed_bitfields && !declspecs->explicit_signed_p
&& TREE_CODE (type) == INTEGER_TYPE)
type = unsigned_type_for (type);
C++ front-end:
/* Decide whether an integer type is signed or not.
Optionally treat bitfields as signed by default. */
if (unsigned_p
/* [class.bit]
It is implementation-defined whether a plain (neither
explicitly signed or unsigned) char, short, int, or long
bit-field is signed or unsigned.
Naturally, we extend this to long long as well. Note that
this does not include wchar_t. */
|| (bitfield && !flag_signed_bitfields
&& !signed_p
/* A typedef for plain `int' without `signed' can be
controlled just like plain `int', but a typedef for
`signed int' cannot be so controlled. */
&& !(typedef_decl
&& C_TYPEDEF_EXPLICITLY_SIGNED (typedef_decl))
&& TREE_CODE (type) == INTEGER_TYPE
&& !same_type_p (TYPE_MAIN_VARIANT (type), wchar_type_node)))
{
if (explicit_intN)
type = int_n_trees[declspecs->int_n_idx].unsigned_type;
else if (longlong)
type = long_long_unsigned_type_node;
else if (long_p)
type = long_unsigned_type_node;
else if (short_p)
type = short_unsigned_type_node;
else if (type == char_type_node)
type = unsigned_char_type_node;
else if (typedef_decl)
type = unsigned_type_for (type);
else
type = unsigned_type_node;
}
The problem is we have a typedef with aligned attribute on it but in both cases
we lose that.
