https://gcc.gnu.org/bugzilla/show_bug.cgi?id=96911
kargl at gcc dot gnu.org changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |kargl at gcc dot gnu.org --- Comment #2 from kargl at gcc dot gnu.org --- (In reply to zhen.xu from comment #0) > Dealing with Intrinsic shifta/shiftl/shiftr, gfortran refuses proper numbers > in the code below and throws "Error: Integer too big for its kind". > > The code is checked with ifort. > > -------code---------- > program test > print *, shifta(-128_1, 1); > print *, shifta(-32768_2, 1); > print *, shifta(-2147483648_4, 1); > print *, shifta(-9223372036854775808_8, 1); > > print *, shiftl(-128_1, 1); > print *, shiftl(-32768_2, 1); > print *, shiftl(-2147483648_4, 1); > print *, shiftl(-9223372036854775808_8, 1); > > print *, shiftr(-128_1, 1); > print *, shiftr(-32768_2, 1); > print *, shiftr(-2147483648_4, 1); > print *, shiftr(-9223372036854775808_8, 1); > > end > ---------------------- There are no negative integer withs gfortran. -128_1 is a unary minus operator and 128_1 is a invalid operand. 128_1 would be greater than huge(1_1). The only way to get the most "negative integer" is to do -huge(1_1) - 1 (assuming twos-complement arithmetic applies).