https://gcc.gnu.org/bugzilla/show_bug.cgi?id=95918
--- Comment #8 from David Edelsohn <dje at gcc dot gnu.org> ---
It uses . where it wants to consume a quotation mark (").
Because the BE/LE difference is flipping characters, would it negate the
purpose of the test to check for one or zero characters?
! { dg-final { scan-tree-dump { \(\*var\.str2\)\[1\]{lb: 1 sz: 4} =
.d?\\x00\\x00d?.\[1\]{lb: 1 sz: 4};} "original" } }
In other words, test for the "d" or not at one end, and "d" or not at the other
end.
And the next test would become
! { dg-final { scan-tree-dump " __builtin_memmove \(\(void \*\) &\(\*var.
str2\)\[2\]{lb: 1 sz: 4}, \(void \*\\) &.e?\\x00\\x00\\x00[ef]\\x00
\\x00f?.\[1\]{lb: 1 sz: 4}, 8\);" "original" } }
Or is a possible failure that the endian was flipped?
