https://gcc.gnu.org/bugzilla/show_bug.cgi?id=93807
Marek Polacek <mpolacek at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Ever confirmed|0 |1
Status|UNCONFIRMED |ASSIGNED
Keywords|accepts-invalid |
CC| |mpolacek at gcc dot gnu.org
Last reconfirmed| |2020-04-21
Assignee|unassigned at gcc dot gnu.org |mpolacek at gcc dot
gnu.org
--- Comment #2 from Marek Polacek <mpolacek at gcc dot gnu.org> ---
I think this is valid code: C++20 [temp.names]/2 says "A name is also
considered to refer to a template if it is an unqualified-id followed by a <
and name lookup either finds one or more functions or finds nothing." so when
we're parsing
constexpr friend bool operator==<T>(T lhs, const Foo& rhs);
we treat "operator==" as a template name, because name lookup of "operator=="
found nothing and we have an operator-function-id, which is an unqualified-id.
So the declaration isn't needed to treat "operator==<T>" as a template-id.
I'll add the test.
