https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82643
--- Comment #7 from CVS Commits <cvs-commit at gcc dot gnu.org> --- The releases/gcc-8 branch has been updated by Jason Merrill <ja...@gcc.gnu.org>: https://gcc.gnu.org/g:6470e8caa2bd331fb6e21524d6c14662531cfa9b commit r8-10072-g6470e8caa2bd331fb6e21524d6c14662531cfa9b Author: Jason Merrill <ja...@redhat.com> Date: Tue Feb 25 21:29:03 2020 -0500 PR c++/86429 - constexpr variable in lambda. When we refer to a captured variable from a constant-expression context inside a lambda, the closure (like any function parameter) is not constant because we aren't in a call, so we don't have an argument. So the capture is non-constant. But if the captured variable is constant, we might be able to use it directly in constexpr evaluation. gcc/cp/ChangeLog 2020-02-25 Jason Merrill <ja...@redhat.com> PR c++/86429 - constexpr variable in lambda. PR c++/82643 PR c++/87327 * constexpr.c (cxx_eval_constant_expression): In a lambda function, try evaluating the captured variable directly.
