https://gcc.gnu.org/bugzilla/show_bug.cgi?id=92787
Bug ID: 92787
Summary: P0634R3 is not implemented correctly if
parameter-declaration appears in a default argument
Product: gcc
Version: 10.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: boostcpp at gmail dot com
Target Milestone: ---
The lambda expression's parameter-declaration don't assume a qualified-id to
name a type if that parameter-declaration appears in a default argument.
> parameter-declaration in a lambda-declarator, unless that
> parameter-declaration appears in a default argument, or
parameter-declaration of a (non-type) template-parameter.
template < typename T >
// lambda expression's parameter-declaration appears in a default argument
void f( typename T::type x = []( T::type x ){return x ;}( typename T::type{})
)
{
}
https://wandbox.org/permlink/7d2d6aqjZWOhL5Pq
But current GCC 10 head assume it to name a type.
Or am I reading the wording wrong?
