https://gcc.gnu.org/bugzilla/show_bug.cgi?id=91432
Bug ID: 91432
Summary: gcc -Wimplicit-fallthrough does not warn when
fallthrough to break;
Product: gcc
Version: unknown
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
Assignee: unassigned at gcc dot gnu.org
Reporter: joe at perches dot com
Target Milestone: ---
This code does not emit a fallthrough warning:
int foo(int i)
{
switch (i) {
case 1:
i = 0;
default:
break;
}
return i;
}
Basically any case block that falls through to another
block of just a break statement does not get a warning.
Is this a defect or what was the logic behind this decision?
