https://gcc.gnu.org/bugzilla/show_bug.cgi?id=88626
Richard Biener <rguenth at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |NEW
Last reconfirmed| |2019-01-02
Ever confirmed|0 |1
--- Comment #2 from Richard Biener <rguenth at gcc dot gnu.org> ---
The __builtin_constant_p call itself is "free" but whether guarded code is
"free" isn't easy to determine. I guess what you want is the computation
of "b" which is only used when it is constant is considered "free"?
Confirmed for that. Not sure how easy to implement though.
