https://gcc.gnu.org/bugzilla/show_bug.cgi?id=85557
Jonathan Wakely <redi at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Keywords| |wrong-code
Status|WAITING |NEW
--- Comment #3 from Jonathan Wakely <redi at gcc dot gnu.org> ---
"The initialization of a parameter, including every associated value
computation and side effect, is indeterminately sequenced with respect to that
of any other parameter."
That's indeterminately sequenced, not unsequenced:
"Evaluations A and B are indeterminately sequenced when either A is sequenced
before B or B is sequenced before A, but it is unspecified which. [ Note:
Indeterminately sequenced evaluations cannot overlap, but either could
be executed first. — end note ]"
So the function is called as foo(1, 2), but it's unspecified whether i==1 or
i==2 afterwards.
