[Bug middle-end/83557] New: missing last char in printf fmt string

[x37a5709 at gmail dot com]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=83557

            Bug ID: 83557
           Summary: missing last char in printf fmt string
           Product: gcc
           Version: 4.9.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: middle-end
          Assignee: unassigned at gcc dot gnu.org
          Reporter: x37a5709 at gmail dot com
  Target Milestone: ---

gcc compiler for m68k code generation
m68k-rtems4.11-gcc (GCC) 4.9.3 20150626 (RTEMS 4.11, RSB no-repo, Newlib
2.2.0.20150423)
Copyright (C) 2015 Free Software Foundation, Inc.

The following c -statement for printf (possibly always within a while, for and
if statement) does not result into a proper implementation

    printf("\r\n");

AS list code
 485                    .LC5:
 486                            .string "\r"
 163:init68360.c   ****   char *txt = "\r\n\n68360 Boot Monitor (%s)\r\n\n";


Work arounds are:

printf("\r\n",' '); /* extra argument in printf call */

485                     .LC5:
 486                            .string "\r\n"
 163:init68360.c   ****   char *txt = "\r\n\n68360 Boot Monitor (%s)\r\n\n";

printf("\r\n "); /* string enhanced with blank */

 485                    .LC5:
 486                            .string "\r\n "
 163:init68360.c   ****   char *txt = "\r\n\n68360 Boot Monitor (%s)\r\n\n";


printf("\r\n \b"); /* string enhanced with white space and backspace */

485                     .LC5:
 486                            .string "\r\n \b"
 163:init68360.c   ****   char *txt = "\r\n\n68360 Boot Monitor (%s)\r\n\n";