https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82051
Richard Biener <rguenth at gcc dot gnu.org> changed:
What |Removed |Added
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CC| |rguenth at gcc dot gnu.org
--- Comment #2 from Richard Biener <rguenth at gcc dot gnu.org> ---
(In reply to Andrew Pinski from comment #1)
> I don't know if this is defined or not. Basically 0x549E5CE9L is really
> 0xCE9 which is stored in the bit-field. The rest of the bits might be still
> undefined or zero. I don't remember what the C standard says here.
They are undefined. The question is what the standard says about the
initializer, what union member gets initialized / activated. One may read
6.7.9/20 as to
always the first member being initialized / activated.
In this case this PR is INVALID.
I suppose you want = { .f1 = 0x549E5CE9L };
