https://gcc.gnu.org/bugzilla/show_bug.cgi?id=81134
Jonathan Wakely <redi at gcc dot gnu.org> changed: What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution|--- |INVALID --- Comment #1 from Jonathan Wakely <redi at gcc dot gnu.org> --- This is not a bug, the conditional expression using ?: instantiates both branches, so although one branch uses the terminating case, the other one doesn't. You can make the code valid like this: template <int N, int M> struct GCD { static const int value = std::conditional<(N>M), GCD<N%M, M>, GCD<N, M%N>>::type::value; }; Or like this: template <int N, int M> struct GCD : std::conditional<(N>M), GCD<N%M, M>, GCD<N, M%N>>::type { };