https://gcc.gnu.org/bugzilla/show_bug.cgi?id=80138
--- Comment #1 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
So the reason why it disappears with: "(w >= y) && (w < y+h)" is that GCC has
only one bit to say if we should not warn again on an expression and using ()
causes that bit to be set :). GCC needs more bits for that but nobody has
decided to fix that.
as for the warning being spurious, I don't think it is.
We have:
if (!(y >= r.y && y < r.y + r.h)) {
int yc = r.y+10;
if (yc >= r.y && yc < r.y + r.h) {
return 1;
}
}
So take:
int yc = r.y+10;
if (yc >= r.y && yc < r.y + r.h)
You have:
int yc = r.y+10;
if (r.y+10 >= r.y && r.y+10 < r.y + r.h)
Well r.y+10 >= r.y is causing the warning.
