https://gcc.gnu.org/bugzilla/show_bug.cgi?id=69736

--- Comment #4 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
(fn1)();
is no longer the same as fn1();
But rather it returns an rvalue reference.  So it no longer includes the
default arguments as part of the type.  That is function types don't have
default arguments.

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