https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66077
--- Comment #2 from Mike Jost <mike.jost at hp dot com> --- Thanks for the explanation! Bit by the 64 bit. That will teach me to use uint32_t instead of assuming 32 for unsigned long. I've been running on 32 bit embedded targets for too long! Regards, Michael Jost mike.j...@hp.com Software Engineer Object Technology Solutions, Inc. (OTSI) contractor HP Roseville - R3U Q8 (916) 785-2815 -----Original Message----- From: pinskia at gcc dot gnu.org [mailto:gcc-bugzi...@gcc.gnu.org] Sent: Friday, May 08, 2015 11:40 AM To: Jost, Mike (OTSI Contractor) Subject: [Bug c/66077] Right shift calculation error https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66077 Andrew Pinski <pinskia at gcc dot gnu.org> changed: What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution|--- |INVALID --- Comment #1 from Andrew Pinski <pinskia at gcc dot gnu.org> --- Your X and Y are not correctly displaying. The correct values are: x = 0xF12B3740 y = 0x1F12B3740 You should be using %lX rather than %X to display unsigned long. Like: printf("x = 0x%lX\n", x); printf("y = 0x%lX\n", y); As you can see there is another bit set in the upper 32bits which causes the difference. -- You are receiving this mail because: You reported the bug.
