https://gcc.gnu.org/bugzilla/show_bug.cgi?id=62046
Bug ID: 62046
Summary: A catch in a class, without any try, compiles fine
Product: gcc
Version: 4.8.1
Status: UNCONFIRMED
Severity: minor
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: gcc at themudrest dot com
A catch can follow a method in a class, without any try. Isn't this a syntax
error? We couldn't find anything in the standard explaining it.
This is a vector for bugs in code, if your forget to include the try after a
method, the expected catch for throws in the method is not called.
Example code:
#include <iostream>
class TestTry
{
public:
// if you include the try after the method
// it is caught below, but if you forget it is not
void FunctionCatch() /*** No try here! ***/
{
std::cout << "FunctionCatch" << std::endl;
throw 42;
std::cout << "FunctionCatch post-throw" << std::endl;
}
// what is this catch doing here?
// shouldn't this be a compile error?
catch (...)
{
std::cout << "FunctionCatch caught!" << std::endl;
}
};
int main(int argc, char *argv[])
{
TestTry Object;
try
{
Object.FunctionCatch();
}
catch (...)
{
std::cout << "caught in main" << std::endl;
}
}
> g++ -Wall TestTry.cpp
> ./a.out
FunctionCatch
caught in main
