https://gcc.gnu.org/bugzilla/show_bug.cgi?id=61489
--- Comment #3 from Deniz Bahadir <D.Bahadir at GMX dot de> --- Thanks for the comment. So, at least we aggree that the cases for addr2 and addr6 should not warn (in C++11) as it initializes all values. Possibly this holds true for addr9, too? I always thought that the cases for addr3 and addr7 (and maybe also addr4 and addr8) should initialize the entire struct with zeros. (This is for example mentioned in that explanation: http://www.codeguru.com/cpp/cpp/article.php/c19081/C-2011-Uniform-Initialization.htm) By a quick look through the C++11 standard I was not able to find the section which states that. However, I found something similar in section "8.5.1 Aggregates", paragraph 7: "If there are fewer initializer-clauses in the list than there are members in the aggregate, then each member not explicitly initialized shall be initialized from an empty initializer list (8.5.4). [ Example: struct S { int a; const char* b; int c; }; S ss = { 1, "asdf" }; initializes ss.a with 1, ss.b with "asdf", and ss.c with the value of an expression of the form int(), that is, 0. —end example ]" So, I am unsure if the compiler should warn about that or not. Could maybe someone clarify if the statement from the link above about the cases addr3 and addr7 is correct?
