http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60838
Bug ID: 60838 Summary: bugos warning: initializer element is not a constant expression: int test = (0 ? (1,0) : 0) + 1; Product: gcc Version: unknown Status: UNCONFIRMED Severity: minor Priority: P3 Component: c Assignee: unassigned at gcc dot gnu.org Reporter: potrepa...@asc-ural.ru main.c: ------------- int test = (0 ? (3, 0) : 0) + 1; int main( void ) { return 0; } ------------- >gcc main.c main.c:1:12: warning: initializer element is not a constant expression This is work, but generate warning: #define CT_ASSERT_EXPR(ex) (0 ? ((struct { int a:((ex) ? 1 : -1); } *)0,0) : 0) #define CT_ASSERT(ex) extern char ct_assert_[ CT_ASSERT_EXPR(ex)+1 ] warning: variably modified 'ct_assert_' at file scope According C standart: 6.6 Constant expressions Constant expressions shall not contain assignment, increment, decrement, function-call, or comma operators, except when they are contained within a subexpression that is not evaluated. 6.5.15 Conditional operator The first operand is evaluated; there is a sequence point after its evaluation. The second operand is evaluated only if the first compares unequal to 0; the third operand is evaluated only if the first compares equal to 0; the result is the value of the second or third operand (whichever is evaluated), converted to the type described below.