http://gcc.gnu.org/bugzilla/show_bug.cgi?id=56488
--- Comment #4 from Jakub Jelinek <jakub at gcc dot gnu.org> 2013-03-01 09:59:39 UTC --- But e = e + 5 is avaluated as e = (short) ((int) e + 5) and thus I think it just falls down to implementation defined behavior (assuming short is smaller than int of course), because no overflow happens in the int type in which the addition is computed, and there is just cast of a larger int value to smaller short type.
