http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55806
--- Comment #3 from Thomas Koenig <tkoenig at gcc dot gnu.org> 2013-01-14 22:29:37 UTC --- Now for something harder (which is Michael Metcalf's original idiom): if (any([a(1),a(2)]>acc) then... This can be done by converting [a1, a2, ...] binop scalar to [a1 binop scalar, a2 binop scalar, ...] in general, followed by what has been committed already.
